3.3.61 \(\int \frac {x^4 (a+b \log (c (d+e x)^n))}{f+g x^2} \, dx\) [261]

3.3.61.1 Optimal result
3.3.61.2 Mathematica [A] (verified)
3.3.61.3 Rubi [A] (verified)
3.3.61.4 Maple [C] (warning: unable to verify)
3.3.61.5 Fricas [F]
3.3.61.6 Sympy [F(-1)]
3.3.61.7 Maxima [F]
3.3.61.8 Giac [F]
3.3.61.9 Mupad [F(-1)]

3.3.61.1 Optimal result

Integrand size = 27, antiderivative size = 369 \[ \int \frac {x^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x^2} \, dx=-\frac {a f x}{g^2}+\frac {b f n x}{g^2}-\frac {b d^2 n x}{3 e^2 g}+\frac {b d n x^2}{6 e g}-\frac {b n x^3}{9 g}+\frac {b d^3 n \log (d+e x)}{3 e^3 g}-\frac {b f (d+e x) \log \left (c (d+e x)^n\right )}{e g^2}+\frac {x^3 \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 g}+\frac {(-f)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e \left (\sqrt {-f}-\sqrt {g} x\right )}{e \sqrt {-f}+d \sqrt {g}}\right )}{2 g^{5/2}}-\frac {(-f)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e \left (\sqrt {-f}+\sqrt {g} x\right )}{e \sqrt {-f}-d \sqrt {g}}\right )}{2 g^{5/2}}-\frac {b (-f)^{3/2} n \operatorname {PolyLog}\left (2,-\frac {\sqrt {g} (d+e x)}{e \sqrt {-f}-d \sqrt {g}}\right )}{2 g^{5/2}}+\frac {b (-f)^{3/2} n \operatorname {PolyLog}\left (2,\frac {\sqrt {g} (d+e x)}{e \sqrt {-f}+d \sqrt {g}}\right )}{2 g^{5/2}} \]

output
-a*f*x/g^2+b*f*n*x/g^2-1/3*b*d^2*n*x/e^2/g+1/6*b*d*n*x^2/e/g-1/9*b*n*x^3/g 
+1/3*b*d^3*n*ln(e*x+d)/e^3/g-b*f*(e*x+d)*ln(c*(e*x+d)^n)/e/g^2+1/3*x^3*(a+ 
b*ln(c*(e*x+d)^n))/g+1/2*(-f)^(3/2)*(a+b*ln(c*(e*x+d)^n))*ln(e*((-f)^(1/2) 
-x*g^(1/2))/(e*(-f)^(1/2)+d*g^(1/2)))/g^(5/2)-1/2*(-f)^(3/2)*(a+b*ln(c*(e* 
x+d)^n))*ln(e*((-f)^(1/2)+x*g^(1/2))/(e*(-f)^(1/2)-d*g^(1/2)))/g^(5/2)-1/2 
*b*(-f)^(3/2)*n*polylog(2,-(e*x+d)*g^(1/2)/(e*(-f)^(1/2)-d*g^(1/2)))/g^(5/ 
2)+1/2*b*(-f)^(3/2)*n*polylog(2,(e*x+d)*g^(1/2)/(e*(-f)^(1/2)+d*g^(1/2)))/ 
g^(5/2)
 
3.3.61.2 Mathematica [A] (verified)

Time = 0.20 (sec) , antiderivative size = 339, normalized size of antiderivative = 0.92 \[ \int \frac {x^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x^2} \, dx=\frac {-18 a f \sqrt {g} x+18 b f \sqrt {g} n x-\frac {b g^{3/2} n \left (e x \left (6 d^2-3 d e x+2 e^2 x^2\right )-6 d^3 \log (d+e x)\right )}{e^3}-\frac {18 b f \sqrt {g} (d+e x) \log \left (c (d+e x)^n\right )}{e}+6 g^{3/2} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right )+9 (-f)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e \left (\sqrt {-f}-\sqrt {g} x\right )}{e \sqrt {-f}+d \sqrt {g}}\right )+9 \sqrt {-f} f \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e \left (\sqrt {-f}+\sqrt {g} x\right )}{e \sqrt {-f}-d \sqrt {g}}\right )-9 b (-f)^{3/2} n \operatorname {PolyLog}\left (2,-\frac {\sqrt {g} (d+e x)}{e \sqrt {-f}-d \sqrt {g}}\right )+9 b (-f)^{3/2} n \operatorname {PolyLog}\left (2,\frac {\sqrt {g} (d+e x)}{e \sqrt {-f}+d \sqrt {g}}\right )}{18 g^{5/2}} \]

input
Integrate[(x^4*(a + b*Log[c*(d + e*x)^n]))/(f + g*x^2),x]
 
output
(-18*a*f*Sqrt[g]*x + 18*b*f*Sqrt[g]*n*x - (b*g^(3/2)*n*(e*x*(6*d^2 - 3*d*e 
*x + 2*e^2*x^2) - 6*d^3*Log[d + e*x]))/e^3 - (18*b*f*Sqrt[g]*(d + e*x)*Log 
[c*(d + e*x)^n])/e + 6*g^(3/2)*x^3*(a + b*Log[c*(d + e*x)^n]) + 9*(-f)^(3/ 
2)*(a + b*Log[c*(d + e*x)^n])*Log[(e*(Sqrt[-f] - Sqrt[g]*x))/(e*Sqrt[-f] + 
 d*Sqrt[g])] + 9*Sqrt[-f]*f*(a + b*Log[c*(d + e*x)^n])*Log[(e*(Sqrt[-f] + 
Sqrt[g]*x))/(e*Sqrt[-f] - d*Sqrt[g])] - 9*b*(-f)^(3/2)*n*PolyLog[2, -((Sqr 
t[g]*(d + e*x))/(e*Sqrt[-f] - d*Sqrt[g]))] + 9*b*(-f)^(3/2)*n*PolyLog[2, ( 
Sqrt[g]*(d + e*x))/(e*Sqrt[-f] + d*Sqrt[g])])/(18*g^(5/2))
 
3.3.61.3 Rubi [A] (verified)

Time = 0.63 (sec) , antiderivative size = 369, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.074, Rules used = {2863, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {x^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x^2} \, dx\)

\(\Big \downarrow \) 2863

\(\displaystyle \int \left (\frac {f^2 \left (a+b \log \left (c (d+e x)^n\right )\right )}{g^2 \left (f+g x^2\right )}-\frac {f \left (a+b \log \left (c (d+e x)^n\right )\right )}{g^2}+\frac {x^2 \left (a+b \log \left (c (d+e x)^n\right )\right )}{g}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {(-f)^{3/2} \log \left (\frac {e \left (\sqrt {-f}-\sqrt {g} x\right )}{d \sqrt {g}+e \sqrt {-f}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{2 g^{5/2}}-\frac {(-f)^{3/2} \log \left (\frac {e \left (\sqrt {-f}+\sqrt {g} x\right )}{e \sqrt {-f}-d \sqrt {g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{2 g^{5/2}}+\frac {x^3 \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 g}-\frac {a f x}{g^2}-\frac {b f (d+e x) \log \left (c (d+e x)^n\right )}{e g^2}+\frac {b d^3 n \log (d+e x)}{3 e^3 g}-\frac {b d^2 n x}{3 e^2 g}-\frac {b (-f)^{3/2} n \operatorname {PolyLog}\left (2,-\frac {\sqrt {g} (d+e x)}{e \sqrt {-f}-d \sqrt {g}}\right )}{2 g^{5/2}}+\frac {b (-f)^{3/2} n \operatorname {PolyLog}\left (2,\frac {\sqrt {g} (d+e x)}{\sqrt {g} d+e \sqrt {-f}}\right )}{2 g^{5/2}}+\frac {b d n x^2}{6 e g}+\frac {b f n x}{g^2}-\frac {b n x^3}{9 g}\)

input
Int[(x^4*(a + b*Log[c*(d + e*x)^n]))/(f + g*x^2),x]
 
output
-((a*f*x)/g^2) + (b*f*n*x)/g^2 - (b*d^2*n*x)/(3*e^2*g) + (b*d*n*x^2)/(6*e* 
g) - (b*n*x^3)/(9*g) + (b*d^3*n*Log[d + e*x])/(3*e^3*g) - (b*f*(d + e*x)*L 
og[c*(d + e*x)^n])/(e*g^2) + (x^3*(a + b*Log[c*(d + e*x)^n]))/(3*g) + ((-f 
)^(3/2)*(a + b*Log[c*(d + e*x)^n])*Log[(e*(Sqrt[-f] - Sqrt[g]*x))/(e*Sqrt[ 
-f] + d*Sqrt[g])])/(2*g^(5/2)) - ((-f)^(3/2)*(a + b*Log[c*(d + e*x)^n])*Lo 
g[(e*(Sqrt[-f] + Sqrt[g]*x))/(e*Sqrt[-f] - d*Sqrt[g])])/(2*g^(5/2)) - (b*( 
-f)^(3/2)*n*PolyLog[2, -((Sqrt[g]*(d + e*x))/(e*Sqrt[-f] - d*Sqrt[g]))])/( 
2*g^(5/2)) + (b*(-f)^(3/2)*n*PolyLog[2, (Sqrt[g]*(d + e*x))/(e*Sqrt[-f] + 
d*Sqrt[g])])/(2*g^(5/2))
 

3.3.61.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2863
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((h_.)*(x_)) 
^(m_.)*((f_) + (g_.)*(x_)^(r_.))^(q_.), x_Symbol] :> Int[ExpandIntegrand[(a 
 + b*Log[c*(d + e*x)^n])^p, (h*x)^m*(f + g*x^r)^q, x], x] /; FreeQ[{a, b, c 
, d, e, f, g, h, m, n, p, q, r}, x] && IntegerQ[m] && IntegerQ[q]
 
3.3.61.4 Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 1.17 (sec) , antiderivative size = 606, normalized size of antiderivative = 1.64

method result size
risch \(\frac {b \ln \left (\left (e x +d \right )^{n}\right ) x^{3}}{3 g}+\frac {b \,d^{3} \ln \left (\left (e x +d \right )^{n}\right )}{3 e^{3} g}-\frac {b \ln \left (\left (e x +d \right )^{n}\right ) f x}{g^{2}}-\frac {b d f \ln \left (\left (e x +d \right )^{n}\right )}{e \,g^{2}}-\frac {b \,f^{2} \arctan \left (\frac {2 g \left (e x +d \right )-2 d g}{2 e \sqrt {f g}}\right ) n \ln \left (e x +d \right )}{g^{2} \sqrt {f g}}+\frac {b \,f^{2} \arctan \left (\frac {2 g \left (e x +d \right )-2 d g}{2 e \sqrt {f g}}\right ) \ln \left (\left (e x +d \right )^{n}\right )}{g^{2} \sqrt {f g}}-\frac {b n \,x^{3}}{9 g}+\frac {b d n \,x^{2}}{6 e g}-\frac {b \,d^{2} n x}{3 e^{2} g}-\frac {11 b \,d^{3} n}{18 e^{3} g}+\frac {b f n x}{g^{2}}+\frac {b d f n}{e \,g^{2}}+\frac {b n \,f^{2} \ln \left (e x +d \right ) \ln \left (\frac {e \sqrt {-f g}-g \left (e x +d \right )+d g}{e \sqrt {-f g}+d g}\right )}{2 g^{2} \sqrt {-f g}}-\frac {b n \,f^{2} \ln \left (e x +d \right ) \ln \left (\frac {e \sqrt {-f g}+g \left (e x +d \right )-d g}{e \sqrt {-f g}-d g}\right )}{2 g^{2} \sqrt {-f g}}+\frac {b n \,f^{2} \operatorname {dilog}\left (\frac {e \sqrt {-f g}-g \left (e x +d \right )+d g}{e \sqrt {-f g}+d g}\right )}{2 g^{2} \sqrt {-f g}}-\frac {b n \,f^{2} \operatorname {dilog}\left (\frac {e \sqrt {-f g}+g \left (e x +d \right )-d g}{e \sqrt {-f g}-d g}\right )}{2 g^{2} \sqrt {-f g}}+\left (-\frac {i b \pi \,\operatorname {csgn}\left (i c \left (e x +d \right )^{n}\right ) \operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i \left (e x +d \right )^{n}\right )}{2}+\frac {i \pi \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2} b}{2}+\frac {i \pi \,\operatorname {csgn}\left (i \left (e x +d \right )^{n}\right ) \operatorname {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2} b}{2}-\frac {i \pi \operatorname {csgn}\left (i c \left (e x +d \right )^{n}\right )^{3} b}{2}+b \ln \left (c \right )+a \right ) \left (\frac {\frac {1}{3} g \,x^{3}-f x}{g^{2}}+\frac {f^{2} \arctan \left (\frac {g x}{\sqrt {f g}}\right )}{g^{2} \sqrt {f g}}\right )\) \(606\)

input
int(x^4*(a+b*ln(c*(e*x+d)^n))/(g*x^2+f),x,method=_RETURNVERBOSE)
 
output
1/3*b*ln((e*x+d)^n)/g*x^3+1/3*b/e^3/g*d^3*ln((e*x+d)^n)-b*ln((e*x+d)^n)/g^ 
2*f*x-b/e/g^2*d*f*ln((e*x+d)^n)-b*f^2/g^2/(f*g)^(1/2)*arctan(1/2*(2*g*(e*x 
+d)-2*d*g)/e/(f*g)^(1/2))*n*ln(e*x+d)+b*f^2/g^2/(f*g)^(1/2)*arctan(1/2*(2* 
g*(e*x+d)-2*d*g)/e/(f*g)^(1/2))*ln((e*x+d)^n)-1/9*b*n*x^3/g+1/6*b*d*n*x^2/ 
e/g-1/3*b*d^2*n*x/e^2/g-11/18*b*d^3*n/e^3/g+b*f*n*x/g^2+b*d*f*n/e/g^2+1/2* 
b*n*f^2/g^2*ln(e*x+d)/(-f*g)^(1/2)*ln((e*(-f*g)^(1/2)-g*(e*x+d)+d*g)/(e*(- 
f*g)^(1/2)+d*g))-1/2*b*n*f^2/g^2*ln(e*x+d)/(-f*g)^(1/2)*ln((e*(-f*g)^(1/2) 
+g*(e*x+d)-d*g)/(e*(-f*g)^(1/2)-d*g))+1/2*b*n*f^2/g^2/(-f*g)^(1/2)*dilog(( 
e*(-f*g)^(1/2)-g*(e*x+d)+d*g)/(e*(-f*g)^(1/2)+d*g))-1/2*b*n*f^2/g^2/(-f*g) 
^(1/2)*dilog((e*(-f*g)^(1/2)+g*(e*x+d)-d*g)/(e*(-f*g)^(1/2)-d*g))+(-1/2*I* 
b*Pi*csgn(I*c)*csgn(I*(e*x+d)^n)*csgn(I*c*(e*x+d)^n)+1/2*I*b*Pi*csgn(I*c)* 
csgn(I*c*(e*x+d)^n)^2+1/2*I*b*Pi*csgn(I*(e*x+d)^n)*csgn(I*c*(e*x+d)^n)^2-1 
/2*I*b*Pi*csgn(I*c*(e*x+d)^n)^3+b*ln(c)+a)*(1/g^2*(1/3*g*x^3-f*x)+f^2/g^2/ 
(f*g)^(1/2)*arctan(g*x/(f*g)^(1/2)))
 
3.3.61.5 Fricas [F]

\[ \int \frac {x^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x^2} \, dx=\int { \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} x^{4}}{g x^{2} + f} \,d x } \]

input
integrate(x^4*(a+b*log(c*(e*x+d)^n))/(g*x^2+f),x, algorithm="fricas")
 
output
integral((b*x^4*log((e*x + d)^n*c) + a*x^4)/(g*x^2 + f), x)
 
3.3.61.6 Sympy [F(-1)]

Timed out. \[ \int \frac {x^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x^2} \, dx=\text {Timed out} \]

input
integrate(x**4*(a+b*ln(c*(e*x+d)**n))/(g*x**2+f),x)
 
output
Timed out
 
3.3.61.7 Maxima [F]

\[ \int \frac {x^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x^2} \, dx=\int { \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} x^{4}}{g x^{2} + f} \,d x } \]

input
integrate(x^4*(a+b*log(c*(e*x+d)^n))/(g*x^2+f),x, algorithm="maxima")
 
output
1/3*a*(3*f^2*arctan(g*x/sqrt(f*g))/(sqrt(f*g)*g^2) + (g*x^3 - 3*f*x)/g^2) 
+ b*integrate((x^4*log((e*x + d)^n) + x^4*log(c))/(g*x^2 + f), x)
 
3.3.61.8 Giac [F]

\[ \int \frac {x^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x^2} \, dx=\int { \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} x^{4}}{g x^{2} + f} \,d x } \]

input
integrate(x^4*(a+b*log(c*(e*x+d)^n))/(g*x^2+f),x, algorithm="giac")
 
output
integrate((b*log((e*x + d)^n*c) + a)*x^4/(g*x^2 + f), x)
 
3.3.61.9 Mupad [F(-1)]

Timed out. \[ \int \frac {x^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x^2} \, dx=\int \frac {x^4\,\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )}{g\,x^2+f} \,d x \]

input
int((x^4*(a + b*log(c*(d + e*x)^n)))/(f + g*x^2),x)
 
output
int((x^4*(a + b*log(c*(d + e*x)^n)))/(f + g*x^2), x)